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By Pythagoras’s theorem, a²+b²= c². So x²= 9+16=25 and so by finding the square root of 25, x=5

Substituting y = x-3 into the first equation and expanding brackets:(x-3)²+x² = 6 <=> 2x² -6x +9 =6 <=> 2x² -6x +3 =0Solving by using the quadratic ...

3x + 5y = 19 and4x - 2y = -18Find the common multiple for 3x and 4x to enable it to be cancelled out. In this case it would be 124(3x + 5y) = 4(19) 3(4x - 2y) = 3(-18) 12x + 20y = 76 12x - 6y = -54 12x + ...

x = 10, y = 4

This question is about geometric sequences. The first step in solving this question is identifying that each term is multiplied by 3 to get to the next term.Therefore since the formula for finding the sum...