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Maths
GCSE

Make h the subject of h-36=(3h+18)/i

First, multiply both sides of the equation by 'i' to remove the fraction: i(h-36) = 3h +18 Then, expand the bracket by multiplying 'i' by each of the terms inside (first h then '-36'). Make sure to keep t...

RT
Answered by Rebecca T. Maths tutor
3161 Views

Factorise fully 27x^2 - 3

First, work out what number is a common factor of both terms - in other words what number 'goes into' both 27 and 3? 3 is a factor of both so put 3 outside the bracket. = 3( __ - __) Now work out what goe...

RT
Answered by Rebecca T. Maths tutor
4417 Views

Solve the following set of equations. 3x + 2y = 5, 2x + 3y =6

This question is an example of simultaneous equations. It's very important to show your working on this question otherwise you won't get any marks, even if you get the right answer! All simultaneous quest...

EL
Answered by Errol L. Maths tutor
3782 Views

Solve the equation (x+2)/(x-3)=(x-6)/(x+1) for x.

We need to multiply both sides by the denominator (the bottom of the fraction) in both fractions so we get:(x+2)(x-3)(x+1)/(x-3)=(x-6)(x-3)(x+1)/(x+1)Now, we can see that we can cancel each fraction to ge...

TH
Answered by Tom H. Maths tutor
2854 Views

A shop sells only Apples, Bananas and Mangos. The ratio of Apples to Bananas is 5:11. The next shopper will choose one piece of fruit at random. The probability that they buy a Mango is 0.2. What is the probability that they buy an Apple?

We have the probability of choosing a Mango is 0.2 so the probability of choosing an Apple or Banana is 1-0.2=0.8.Next we use the ratio 5:11 to see that for every (5+11)=16 Apples or Bananas, 5 will be Ap...

GM
Answered by Gregor M. Maths tutor
3677 Views

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