Make h the subject of h-36=(3h+18)/i

First, multiply both sides of the equation by 'i' to remove the fraction: i(h-36) = 3h +18 Then, expand the bracket by multiplying 'i' by each of the terms inside (first h then '-36'). Make sure to keep the right sand of the equation the same. ih - 36i = 3h + 18 Now, rearrange the equation to get everything containing an 'h' on one side. You do this here by subtracting 3h from each side and adding 36i to each side. ih - 3h = 36i + 18 Factorise the left hand side so you only have one 'h' in the equation: h(i-3) = 36i +18 Now you just need to divide each side of the equation by (i-3) to leave h on its own, as the subject.h = (36i + 18)/(i-3)

RT
Answered by Rebecca T. Maths tutor

3387 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Determine the next two terms in this sequence: 2, 7, 9, 16, 25, ... , ...


Work out the value of 2a^2 + b^3 when a = 5 and b = –3


If the area of a sector of a circle is 3*pi cm^2 and the circle has a radius of 6cm, what is the angle of the sector?


How do I find the missing length using trigonometry?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning