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The root of an equation is a point where, when the equation is plotted on a graph, it crosses the x axis. The x axis is the line y = 0, so the roots can be found by setting 0 = ax2 + bx + c whe...
Using the quadratic formula (-b +- sqrt(b^2 -4ac))/2a we can sub substitute a = 1, b=2 and c = -4 to solve. The answer is x = -1 +/- sqrt(5)
Firstly, If L2 is parallel to L1, the gradient of L1 = L2. If we then take the generic equation of any straight line to be: y = mx + c, the m (gradient) of any two parall...
In order to work out 30% off something you can use two methods. I'll explain both.
Method one:
First, identify the integer factors of the constant. In this case -5, has factors -1,5 and 1,-5. Now check to see if the sum of either pair is equal to the value of the coefficient of x. In this case, the...
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