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Let a be the first term

Let d be the common difference

a + d = 7

S₄ = 4/2 (2a +3d) = 12

Simultaneous equation:

a+d =7 // x 6
4a +6d = 12

Differen...

The first step in this solution is to factorise the equation we have been given into the form (ax+b)(cx+d)=0, where a, b, c and d are constants which we need to determine. If we were to expand the bracket...

Let's open out the bracket using the FOIL method (first, outside, inside, last):

(3 + root(a))(4 + root(a)) = 12 + 3root(a) + 4root(a) + (root(a))² = 12 + 7root(a) + a.

Since the ...

This is a simple question where students need to use BIDMAS to solve the equation. The easiest method is to seperate the two sides and solve individually, then combine. Firstly, 3(x+5) multiplies out to g...

Anna: 6 bananas. Ben: 6*2.5 = 15 bananas. Callum: (6+15)/3 = 7 bananas Altogether they have 6 + 15 + 7 bananas = 28 bananas