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Maths
GCSE

Make x the subject of the equation. y = 4( 2 + x )/ (6x -1)

First lets times both sides by (6x -1) y(6x - 1) = 4(2 + x) now lets expand the brackets 6xy - y = 8 + 4x now lets move all the ones with x as a factor onto one side of the equation and the rest on the ot...

OO
Answered by Oliver O. Maths tutor
5081 Views

Calculate the area of a circle of diameter 8cm

Solution: 

We can first write down the formula for the area of a circle which is pi*(radius)^2.

The radius of the circle is half the diameter, so radius= 1/2(8)=4cm.

Therefore the are...

HH
Answered by Headon H. Maths tutor
16885 Views

Rearrange the following making a the subject: (a+2)/5 = 3a+b

(a+2)/5 = 3a+b  ...first, we need to multiply both sides by 5

a + 2 = 5 (3a + b)  ....to be able substract 3a from the right side we need to remove the bracket. We multiply the bracket by 5.

KR
Answered by Katerina R. Maths tutor
3172 Views

Expand the following: (4x+7)(7x-2)

Using the FOIL (Firsts, Outsides, Insides, Lasts) mnemonic, you can expand these two brackets. F: 4x x 7x = 28x^2 O: 4x x -2 = -8x I: 7 x 7x = 49x L: 7 x -2 = -14 Therefore the expansion as a whole is: 28...

GP
Answered by Gem P. Maths tutor
3853 Views

Expand (x-5)(x+6)

  1. expand the brackets X2 + 6x - 5x - 30 2) collect like terms X2 + x - 30
MP
Answered by Misha P. Maths tutor
10298 Views

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