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(Depending on what the pupil wants to get out of this session and their ability I will explain the background of simultaneous equations and draw a graph of two lines and sho that their intersection is the...
Solving simultaneous equations by elimination; firstly you would multiply the first equation by 4 to get another equation which we will name (3), and multiply the second equation by 3 to get another equat...
We need to find numbers that multiply together to give -15. This could be -1 and 15, 1 and -15, -3 and 5, 3 and -5. The numbers we need must add up to -2 as well (from -2x term). Therefore our set must be...
x=((y+2)/3)^1/2
First we will need to factorise the equation.
Start with the 3x^2 term and notice 3 is prime so must have 3x and x terms.
(3x - 9) (x + 1) or (3x + 3) (x - 3)
Setting the brackets to...
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