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Maths
GCSE

Solve the following for X and Y: 2y+4x=14 and x-y=-1

Firstly, Take equation 1 (2y+4x=14) and divide it all by 2. This gives y+2x=7. Next make Y the 'subject' AKA put it on it's own. To do this Subtract 2x from both sides. Now we have Y=7-2X. Here you can se...

TM
Answered by Toby M. Maths tutor
4948 Views

Expand and simplify (5a-2b)(3a-4b)

=(5a x 3a) + (5a x -4b) + (3a x -2b) + (-2b x -4b) =15a^2 - 20ab - 6ab + 8b^2 =15a^2 - 26ab + 8b^2

PI
Answered by Paul I. Maths tutor
10108 Views

Solve the simultaneous equations: x^2 + y^2 = 29 and y - x = 3

To solve these equations we need to eliminate one of the variables, so make y the subject of the second equation: y = x + 3. Now y can be substituted into the first equation: x^2 + (x+3)^2 = 29. Expanding...

TG
Answered by Trisha G. Maths tutor
4170 Views

Solve 3(x-2) = 21

To begin, understanding the basica concept of algebra and multiplication using brackets needs to be covered as I have met quite a few children who have been used to these equations but are still unsure ab...

NF
Answered by Nicole F. Maths tutor
3677 Views

Expand and simplify (6x - 2y)(3x - 7y)

Expand brackets: 18x^2 - 42xy - 6xy + 14y^2 Simplify: 18x^2 - 48xy + 14y^2

3 marks

BW
Answered by Beth W. Maths tutor
6088 Views

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