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Maths
GCSE

Simplify (x^5 * x^8)/(x^4 * x^4).

By using our laws of Indices we know: x^5 * x^12 = x^17 and x^4 * x^4 = x^16

Therefor (x^5 * x^8)/(x^4 * x^4) = x^17/x^16 = x^1 = x.

CM
Answered by Catriona M. Maths tutor
2919 Views

Solve the simultaneous equations x^2 + y^2 = 9 and x+ y = 2. Give your answer to 2.d.p

Label your two equations 1 and 2 respectively. Make x the subject of the second equation, so x=2-y. Substitute x=2-y into x^2+y^2=9, to give (2-y)^2+y^2=9. Expand the brackets using FOIL to give 4-4y+y^2+...

GS
Answered by Georgia S. Maths tutor
31353 Views

Solve the following quadratic equation: x^2 + 3x + 2 = 0

Step 1: Find factors of the constant (The number with no x attached to it), In our case this is 2. The factors of 2 are: 1 & 2 and -1 & -2.

Step 2: The sum of the factors from step 1 must e...

JS
Answered by Jack S. Maths tutor
4198 Views

Solve for x: 2x^2 + 2x -24 = 0

  1. The general formula of a quadratic is ax^2 + bx + c -> this is a quadratic 2) Factorise using common factor (=2) -> 2(x^2 + x - 12) = 0 3) Factorise the quadratic to (x + m)(x + n): the two nu...
YZ
Answered by Yige Z. Maths tutor
10545 Views

Factorise f(x) = x^2+4x+4 and sketch the curve, identifying the roots and minimum point of f(x).

f(x) = (x+2)(x+2) When f(x) = 0, x = -2. f'(x) = 2x + 4 When f'(x) = 0, x = -2, and corresponds to the minimum point. Therefore, the sketch of the curve will be a U-shaped parabola which touches the x-axi...

OD
Answered by Orlaith D. Maths tutor
3637 Views

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