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Maths
GCSE

Solve for X and Y: 2y + x = 7; 3y - x = 8

x=1, y=3; Firstly, rearranging for x in the first equation: x = (7-2y); Substitute this into the second equation: 3y - (7 -2y) = 8; Expand: 3y -7 +2y = 8 (watch negative) 3y +2y = 15 Therefore, 5y = 15 an...

RK
Answered by Ruth K. Maths tutor
5081 Views

A right-angled triangle has side lengths of 8.65cm and 10.15cm. What is the length of its hypotenuse?

Step 1: Draw a labelled diagram of the triangle, marking the side lengths. Step 2: Recall Pythagoras’ theorem equation ‘c2=a2+b2’ Step 3: Substitute the values of a and b into the equation. c2=8.652+10.15...

AM
Answered by Alisha M. Maths tutor
3313 Views

What is the best way to revise for my Maths GCSE?

I believe that there is no better way to revise for Maths than to continually practice questions (especially those that you find most tricky!) The more you practise, the easier you'll find the questions b...

AM
Answered by Alisha M. Maths tutor
3735 Views

How do I solve this pair of simultaneous equations: 3x+y=7 and 3x-y=5?

Step 1: Eliminate the ‘y’ component from the equations by adding the equations together. This gives the new equation ‘6x=12’

Step 2: Find the value of x by dividing both sides of the equation by 6....

AM
Answered by Alisha M. Maths tutor
4269 Views

Rearrange the following to make C the subject (3c+B)/2=C+A

to work this out you need to make the equation equal to C so it will look like C=A+B or something similar. to achieve this you need to change the equation so that C only appears on one side. you would nee...

OR
Answered by Oran R. Maths tutor
4845 Views

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