Search over 10,000 free study notes

Although this may look more complicated than normal, this is just a normal qudratic equation. First by rearranging the equation we can get it into a simpler form, and then we can go about solving it. The ...

Pythagoras' theorem is: a^2+b^2=c^2 (a=short side, b=short side, c=longest side/hypotenuse, ^=squared). Now applying that to this question would mean that a=PQ, b=PR and c=QR. So we can use the figures gi...

15: (x+y+z)/3 = 6 so, x+y+z = 18.Range = highest number - lowest number. For the max range, at least 1 of the numbers must be 1. 1,1,16. 16-1 = 15

Quadractics factorise into double brackets like (x-a)(x-b). We ave to find the facors of -21 which add to make +4. 7 and -3 suffice. (x-3)(x+7) Then x will be equal to 3 and -7 for the equation.

Step 1: Start off by labeling the 2 equations. 3 x + y = 7 will be equation 1. 3 x - y = 5 will be equation 2.

Step 2: rearrange equation 1 to make y the subject. 3 x + y = 7 ---> y = 7 - 3 x (h...