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In order to find the lowest value for X we first need to find the lowest possible value for a and b.

Let us start off with a:

If a is the lowest possible cube number we can ...

We call 3! 'three factorial' and 5! 'five factorial'.

3!=3x2x1

5!=5x4x3x2x1

So our fraction becomes:

(3x2x1) / (5x4x3x2x1) = 6/120

...

We need to solve this so we have a positive x term on one side.

First we can subtract 3 from both sides of the inequality to get:

5x<3x-9

Next we can subtra...

We need to factorise this equation to solve it.

The first step for factorisation is to make the equation equal to zero. We can do this by subtracting x from both sides to get:

...

The first step to eliminate one of the unknowns, in this case x or y. This can be done by making the coefficient (the number before) of one of the unkowns the same number...