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y = 2x^2 + 4x - 8y = 2( x^2 + 2x - 4)Completing the square:y = 2( (x+1)^2 - 1 - 4 )y = 2(x+1)^2 -10the vertex of graph lies at the minimum value of y, and this occurs when x = -1:y = 2(-1+1)^2 -10y = -10t...
s2 - 18s = 0(s + 4)(s - 6) = 0s = -4 s = 6
To prove that (2n+3)2-(2n-3)2 is a multiple of 8 we are going to deal with the first bracket and then the second bracket. When a bracket has 2 next to it, this means that ...
There are numerous alternative ways to solve these simultaneous equations. For this problem, one of the simplest methods is to multiply the first equation by 3, so that we get 6x in both equations:
Rearrange 1/u + 1/v = 1/f
to make u the subject of the formula. Give your answer in its simplest form.
There are a number of ways to approach this problem.
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