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(√12 + √3) squared is just (√12 + √3) mulitipled by itself, so we can rewrite this as

(√12 + √3)*(√12 + √3)

Now we expandthe brackets.

We can mulitply out the ...

So we can always substitute the right terms into the quadratic formula. However, there might be a quicker way. Lets try and see if the quicker ways work.Firstly, we need to spot weather the difference of ...

The general approach to solving simultaneous equations is to replace the ‘y’s in one equation with ‘x’s, or the ‘x’s with ‘y’s.

In this case, we can first take the equation 5x + y = 4 and rear...

Firstly, we can take a look at the degree x's in each term. It seems like they share a common degree of 0. In other words, we will not be able to factor out the x's in the expression.Secondly, we need to ...

We start with 1/(√2 + 1) 

Normally with rationalising surd denominators we multiply the top and bottom of the fraction by the denominator. But this time we have a surd ADDED by a rational...