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Expand first brackets:

4x²+6xy+6xy+9y²

Expand second brackets:

4xy²-6xy-6xy+9y²

Subtract the second e...

Ok, so here are the equations5x+3y=243x-4y=26So let's multiply the first equation by 3, which gives us:15x+9y=72Now let's multiply the second equation by 5, which gives us:15x-20y=130So we're now left wit...

Ok, so we would call this a quadratic equation because it is written in the form of ax^2+bx+c=0 (in our case, a=1, b=6, c=8).Luckily, this type of quadratic equation can be factorised, so we can solve it ...

Let the first equation be equation 1 and the second equation be equation 2.

Firstly, you must substitute equation 1 into equation 2. This is because there are currently two unknown values...

Solve for x: 2x² + 7x + 6 = 0

The first thing to do is look at the left hand side and factorise it. To do this we use the reverse of FOIL. Then when the expres...