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This is a typical exam question which some students may find confusing.The trick to this question is realising that you have to rationalise the denominator. (Topic: Surds)4/(2-√2) = 4/(2-√2) x (2+√2)/(2+√...

3x+6=(x+2)(x-4)

3x+6 = x²-2x-8

x²-5x-14=0

(x-7)(x+2)=0

x=7 so y=27

and x=-2 so y=0

This exercise is asking to prove the existance of the square root of 2. So let's consider the function f(x) = x^2. Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infin...

A simple way to do this is to use substitution. You can pick values for x such as x=0,1,2 and find the values for y. When you have two or more coordinates you can plot the line.

In this c...

This is simple as long as you remember FOIL:
First

Outside

Inside

Last

So, for example, let's multiply out (2x+1)(4x-3)

Multi...