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Why is n^0 always 1 and not 0?

Anything raised to the zeroth power is a difficult thing to get your head around. The easiest explanation (not a full proof) is to look at what happens as we go down in powers of n: n^3=n n n n^2=(n^3)/n=n n...
JC
Answered by Joseph C. • Maths tutor
4992 Views

Sketch the curve y = x^2 - 6x + 5, identifying roots and minima/maxima.

Remeber the formula: (a - b) 2 = a 2 - 2ab + b 2 . Notice that y = x 2 - 2 3 x + 5, so we want to write this using (x - 3 ) 2 = x 2 - 2 3 x* + 9. Taking 4 from both sides gives: (x - 3) 2 - 4 = x 2 - 6x + 5 ...
TD
Answered by Tutor69809 D. • Maths tutor
6145 Views

Solve for x 2x +3 + (4x-1)/2 = 10

2x +3 + (4x-1)/2 = 10 The divisor (2) is the biggest problem right now so we need to get it on its own... (4x-1)/2 = 10-2x-3 Equation has been rearranged! 4x-1 = 2(10-2x-3) Now we can eliminate the divisor b...
SH
Answered by Shannon H. • Maths tutor
5818 Views

Find the centre and radius of the circle with equation: x^2 + y^2 -4x +8y = 5, and determine whether the point (7,-4) lies on the circle.

First we complete the square on the equation of the circle to obtain: (x-2)^2 -4 + (y+4)^2 -16 = 5. Re arrange : (x-2)^2 + (y+4)^2 = 25 General equation of a circle: (x-a)^2 + (y-b)^2 = r^2, with centre (a,b...
AS
Answered by Alec S. • Maths tutor
6661 Views

3(x-2) - 2(x-2)

First expand each set of brackets: (3x - 6) - (2x - 4) Then simplify: 3x - 6 - 2x - (-4) = x - 2
BS
Answered by Beenita S. • Maths tutor
3558 Views