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Maths
GCSE

Solve the simultaneous equations x+2y=4 and x-3y=6

This can be solved in two ways, by substitution or by elimination.Firstly, by substitution, rearrange the first of the two equations in terms of x by subtracting 2y from both sides to get x=4-2y. Then plu...

HM
Answered by Hamish M. Maths tutor
6428 Views

Solve the following equation: 13y - 5 = 9y + 27

13y - 5 = 9y + 2713y - 9y = 27 + 54y = 32y = 32/4y = 8

MG
Answered by Megan G. Maths tutor
3211 Views

Solve the simultaneous equations x^2 + y^2 =13 and x= y - 5.

(y-5)2 + y2 = 13y2-10y +25 + y2=13.2y2-10y+12=0.y2-5y+6=0.(y-3)(y-2)=0. So, y=3 or y=2. Then substituting these values of y back into x=y-...

HD
Answered by Hollie D. Maths tutor
4696 Views

Expand (x+4)(x-4)=33 to give values of x

Use FOIL to expand the brackets. To do this, we start by multiplying the FIRST value in each bracket which in this case is x so we get x^2. Then we multiply the OUTSIDE two values, so here that is x and -...

AB
Answered by Aria B. Maths tutor
3050 Views

How do surds relate to powers and roots?

To understand surds we have to understand powers and there uses. So to start we should look at powers such as what is 22 , 32, and 52. This shows us going up but then we l...

AG
Answered by Alistair G. Maths tutor
2753 Views

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