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We start by trying to find out the values of a and c using the information about the minimum point. We know we can rearrange the right hand side by completing the square: y = a(x^2 + 3x)+cy = a(x+3/2a)^2+...
x2>3(x+6)Firsty expand brackets --> x2>3x+18Then make one side = to 0 ---> x2-3x-18>0Solve the quadratic (x+3)(x-6)>0find the solutions when =0 x=-3 and ...
4 + 5 =9Lionel receives 5/9 x $675 = $375Lionel's mum receives 3/5 x $375 = $225
This can be solved using either substitution or elimination. I think this question is best approached by elimination.By elimination: Multiply the second equation by 5. The minus the first equation ...
90kg x (1.08)^4= 122.44....No, he does not reach his target
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