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Solve the simultaneous equations. 2x+5y=-4 and 7x+y=19

This can be solved using either substitution or elimination. I think this question is best approached by elimination.By elimination: Multiply the second equation by 5. The minus the first equation ...

Answered by Nisha W. • Maths tutor

3300 Views

Sam is a bodybuilder. He currently weighs 90kg, but is aiming to be at 130kg in the next four months. Every month, he puts on 8% of his weight. Does he reach his target?

90kg x (1.08)^4= 122.44....No, he does not reach his target

Answered by ANGELICA S. • Maths tutor

2896 Views

Solve the following equation: 13y - 5 = 9y + 27

13y - 5 = 9y + 2713y - 9y = 27 + 54y = 32y = 32/4y = 8

Answered by Megan G. • Maths tutor

3619 Views

Solve the simultaneous equations x^2 + y^2 =13 and x= y - 5.

(y-5)² + y² = 13y²-10y +25 + y²=13.2y²-10y+12=0.y²-5y+6=0.(y-3)(y-2)=0. So, y=3 or y=2. Then substituting these values of y back into x=y-...

Answered by Hollie D. • Maths tutor

5343 Views

Expand (x+4)(x-4)=33 to give values of x

Use FOIL to expand the brackets. To do this, we start by multiplying the FIRST value in each bracket which in this case is x so we get x^2. Then we multiply the OUTSIDE two values, so here that is x and -...

Answered by Aria B. • Maths tutor

3565 Views