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Maths
GCSE

Solve these simultaneous equations: 7x+3y=84, 2x+2y=32

Make x the subject of either equation:x = (32-2y)/2;x = 16-yRepresent an equation as a function of y only: 7(16-y)+3y = 84;112-7y+3y = 84;112-4y = 84;-4y = -28; y = 7Use the value of y to determine value ...

TP
Answered by Thomas P. Maths tutor
2909 Views

Fully factorise the expression 14x^2y - 28xy^2

First take out a factor of x to give x(14xy - 28y2)Next take out a factor of y to give xy(14x - 28y)Finally take out a factor of 7 to give 7xy(2x - 4y)

SO
Answered by Scarlett O. Maths tutor
3395 Views

Solve the simultaneous equations: 5x+y=21, x-3y=9

Step 1. Take one equation and make either x or y the subject of the formulax=9+3y, 5x+y=21Step 2. Substitute in the equation5(9+3y)+y=21Step 3. Make y the subject of the formula45+15y+y=21 (multiplied out...

MJ
Answered by marcus J. Maths tutor
2677 Views

How do i change a recurring decimal into a fraction?

Let's take 0.666... as an example. In this case we can say x = 0. 666... The next step is to multiply both sides of the equation by 10 so that you end up with 10x = 6.666... Now that we have these 2 equat...

GL
Answered by Gail L. Maths tutor
2660 Views

Write 2x^(2) + 9x + 1 in the from a(x+m)^(2) + n, and hence solve 2x^(2) + 9x + 1= 0, leaving your answer in surd form.

So the first part of the question is about completing the square. Since the coefficient of .. is greater than one, the first step in carrying out this process is to take out the ‘2’ from the equation. Thi...

IS
Answered by Isobel S. Maths tutor
4240 Views

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