Solve the simultaneous equations: 5x+y=21, x-3y=9

Step 1. Take one equation and make either x or y the subject of the formulax=9+3y, 5x+y=21Step 2. Substitute in the equation5(9+3y)+y=21Step 3. Make y the subject of the formula45+15y+y=21 (multiplied out the brackets)16y=-24 (Subtracted 45 from both sides)y=-24/16 (Divided by 16 on both sides)y=-3/2 (Scaled the fraction down) Step 4. Find out what x is equal tox=9+3(-3/2)x=4.5 or 9/2

MJ
Answered by marcus J. Maths tutor

2906 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the inequality 5x + 3 ≤ 3x − 6


Vectors a and b are defined by a = 2i + 3j and b = 4i - 2j, find 3a-b in terms of i and j


When solving two simultaneous equations, when should you use the method of elimination and when would you use the method of substitution?


Solve the simultaneous equations: 2x+2y = 10 and 7x + 4y = 26


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning