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Maths
GCSE

(x+6) and (x+5) are the length and width, respectively, of a rectangle with area 20. Calculate the width of the rectangle.

(x+6)(x+5)=20. x2 + 11x +30=20. x2+ 11x + 10 = 0. (x+10)(x+1)=0 . x=-1 and x=-10. width= -10+5=-5 (invalid solution). width =-1+5= 4. Checking through: (-1+6)*(-1+5)=20.

Answered by Maths tutor
3128 Views

Three points have coordinates A(-8, 6), B(4, 2) and C(-1, 7). The line through C perpendicular to AB intersects AB at the point P. Find the equations of the line AB and CP.

To find the equation of a line, we need; the gradient of that line and a point on that line. To find the gradient of a line, we require two points on the line which have been prov...

RD
Answered by Ryan D. Maths tutor
10377 Views

Expand the brackets (3x^2 + 6x + 7)(x - 3)

To help the student understand how to expand the brackets I would start by splitting the equation to:3x2(x - 3) + 6x(x - 3) + 7(x - 3)I then would ask the student to expand these brackets to:3...

JD
Answered by Jasmine D. Maths tutor
3271 Views

Find the possible values of x from the equation 3(x^2)+2x-4=2(x^2)+3x+8

Here we have an example of a quadratic equation in terms of x. Start by manipulating the equation until it is equal to 0: subtract 2(x^2) from both sides to get (x^2)+2x-4=3x+8. Then subtract 3x from both...

TI
Answered by Tom I. Maths tutor
3860 Views

Factorise fully 6xy + 3y

Step 1: recognise that the common factors of the two terms, 6xy and 3y, are: 3 and y. Step 2: take one common factor, say 3, out of the terms: 3(2xy + y). Step 3: also take the second common factor, y, ou...

GR
Answered by George R. Maths tutor
6378 Views

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