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Maths
GCSE

Which of the following lines is not perpendicular to y=2x+1? (A) y+1/2x=6 (B) 2y=4-x (C) 2x+y=4 (D) y=-1/2(7+x)

First of all, we need to figure out how to tell whether 2 lines are perpendicular. For any equation written in the form 'y=mx+c', the important bit of information we need to answer this question is the va...

OD
Answered by Oliver D. Maths tutor
3040 Views

If two linear equations, y = x + 4 and y = 2x + c, intersect at x = 1, find c.

Draw the two equations, indicating the point of intersections (whiteboard).If the lines intersect at x=1, then at that point the y values of each equation are equivalent. Therefore, x+ 4 = 2x + c.Inputtin...

TD
Answered by Tutor27510 D. Maths tutor
2455 Views

Solve the simultaneous equations: x^2-y=16 and 2y-4=14x

Equations: (1) x^2-y=16 and (2) 2y-4=14xRearrange (2) to give y:2y-4=14x(+4) 2y=14x+4(/2) y=7x+2call the new equation (3) y=7x+2Put (3) into (1):x^2-(7x+2)=16(expand) x^2-7x-2=16(-16) x^2-7x-18=0(Factoris...

HC
Answered by Hollie C. Maths tutor
3552 Views

Rationalise the Denominator: 5+√2/(√3)

To rationalise the denominator without chainging the value of the equation, multiply both the numerator and denominator by the value of the denominator.( (5+√2)/(√3) )*(√3/√3) = ( (5√3)+√6 )/3

MA
Answered by Mohammed A. Maths tutor
2949 Views

Factorise y^2 - y - 12

Looking for a combination of numbers that would multiply to give (-12_ but add together to give (-1)e.g. -6, 2?....-2,6....-4,3 = yes!thus,(y-4)(y+3)

LM
Answered by Lavannya M. Maths tutor
3213 Views

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