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Maths
GCSE

Solve the simultaneous equation: 3x+y =-4 and 3x-4y=6

The first step would be to rearrange the first equation to make y the subject:
3x+y=-4 ----> y=-4-3x
Next we want to substitute this value of y into the second equation
3x-4y=6 ----->...

SP
Answered by Samuel P. Maths tutor
9311 Views

Solve( 3x−2)/4 −(2x+5)/3= (1−x )/6

Firstly, take a common denominator for the left hand-side of the equation which would be 12 and then carrying out the subtraction. After carrying out the subtraction you will be left with two fractions - ...

WR
Answered by Wahid R. Maths tutor
4538 Views

Given X + 3Y = 19 and 2X - Y = 10, find X and Y

This is a simple simultaneous equationFirst we multiply the second equation by 3 to get 6X - 3Y = 30Then we add the first and second equation together to get 6X + X +3Y - 3Y = 30 + 19which we simply to 7X...

GV
Answered by Guillermo V. Maths tutor
3180 Views

Make a the subject of the formula p = (3a + 5)/ (4 - a)

We start by multiplying both sides of the equation by (4 -a). We then expand the brackets "p.(4-a)" and end up with "4p - pa". We then gather the "a's" to one side of the equ...

JP
Answered by Juliana P. Maths tutor
4217 Views

Expand and Simplify (2x+3)(3x-3)

First, take the 2x and multiply each term in the second bracket by it to give 2x.3x=6x2 and 2x.-3= -6x. Then multiply each term of the second bracket by +3 to give 3.3x= 9x and 3.-...

CK
Answered by Charlie K. Maths tutor
6469 Views

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