Solve( 3x−2)/4 −(2x+5)/3= (1−x )/6

Firstly, take a common denominator for the left hand-side of the equation which would be 12 and then carrying out the subtraction. After carrying out the subtraction you will be left with two fractions - one on each side of the equation. Subsequently you do cross multiplication and find the value of x from the linear equation which would be 28/3.
3(3x-2)- 4(2x+5)= 2(1-x)9x-6-8x-20=2-2xx+2x=26+23x=28x=28/3 or 9 1/3

WR
Answered by Wahid R. Maths tutor

5230 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve these simultaneously to find values for a and b: 6a + b = 16 and 5a - 2b = 19


x^2 +y^2 =25, y – 3x = 13 - Simultaneous Equations (June 2017)


Given that your grade for your computing is based on 5 coursework that weigh differently, and you know the results of 4: 80, 75, 50 and 90 which weighs 10%, 20%, 45% and 5%. What grade do you need in your last coursework to achieve at least a B (70%)?


Show that (x+2)(x+3)(x+5) can be written in the form ax^3 + bx^2 + cx +d, where a,b, c and d are positive integers


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning