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First of all you need to spot a way we can add or subtract these two equations together so that we can get rid of one of the terms. This is easily spotted by writing the equations like so:2x - y ...

To factorise an expression of the formax²+bx+c We use the formulaX=(-b+/- (b^2-4ac)^(1/2))/2aExample:Factorise 3X²+2X+-1So here a=3 b=2 c=-1From the formula we get X=1/3 and X=-1And ...

Firstly we have an equation y=4x-6. We are given that x=3 and we want to find y. What we must do is substitute x=3 into the equation to get y: y=4(3)-6 =6

First, multiply out 6x(x^2 - 3) so that it becomes – 6x^2 – 18xThen, multiply (3x^2 + 2) and (2x + 5) so that it becomes 6x^3 + 15x^2 + 4x + 10Add the two results above: 6x^3 + 15x^2 + 4x + 10 – 6x^3 – 18...

Use the formula (n-2)*180 where n is the number of sides on the polygon.