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First begin with rearranging the second equation to put it in terms of Y. Then substitute by putting the second equation (y=3x+13) into equation one as Y^2. Expand (3x+13)^2 and add like terms to form 10x...
2 simultaneous unknown equations. Let x be the number of apples originally, and n the number of fruits in the bag in total originally. i) first scenario, where probability is 1/5, x/n = 1/5 5x= n ii) ...
Begin by multiplying the second equation by three in order to get a 3y value: 9x + 3y = 33. We can now subtract equation one from equation two, 9x + 3y = 33 and 2x + 3y = 19 -->7x + 0y = 14. Resulting ...
Lets start with an example scenario:Two people are to receive a percentage of a £500 business sale. One receives 25% and the other receives 75%. When using percentages we must remember that it means...
x (x-4) = 32X^2-4x-32 = 0(x-8)(x+4) = 0 x=8perimeter =8+4+4+8 = 24cm.
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