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There are a few ways to tackle this particular style of problem. First off we can try doing it without using any bracket theory and just focus on the raw numbers (a somewhat simpler approach). Step 1: We'...
(3x + 1)2 = 9x2 + 6x + 1 (3x - 1)2 = 9x2 - 6x + 1 (9x2 + 6x + 1) - (9x2 - 6x + 1) = 12x 12x/4 = 3x Therefore for all positive integers of ...
To do this we will assume sqrt(2) is rational, a fraction, which means: 21/2 = m/n; m,n belong to integers. Also, m/n is an irreductible fractionJCAnswered by Joao C. • Maths tutor3112 Views
Firstly we will start by expanding the brackets. We will do 2a + 23 for the first bracket, then we will do 5a + 5(-1) for the second bracket which will give us 2a + 6 + 5a - 5. We will ...
In order to solve a quadratic equation by factorisation you must first find the two numbers which add up to - 8 and multiply to get 15. We can do this by trial and error - first listing all of the pairs o...
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