Simultaneously solve these equations 3x+y=7 and 3x-y=5

Method 1 (Elimination) -

You can see that If you add the 2 equations together you can eliminate the y variable like so 6x=12, then if you divide both sides by 6 you get x=2. Then if you place x=2 back into either of the equations you get y=1.

Method 2 (Substitution) -

Take equation 1 and rearrange it so you get y in terms of x, so all the y's on one side and all the x's on the other side. You get y=7-3x. Take this expression for y and put it into equation 2, 3x-y=5. You get 3x - (7-3x) = 5. If you expand out the brackets you get 6x-7=5 and so 6x=12 then dividing both sides by 6, x=2. Like before place x=2 into either equation to get y=1.

CB
Answered by Charlotte B. Maths tutor

4653 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Show that y=3x-2 and 3y-9x+5=0 are parallel.


Denise buys 5 apples and 3 bananas for £3.15. A banana costs 25p more than an apple. How much would it cost to buy 4 apples and 2 bananas?


Solve the simultaneous equations for x and y: 2x - 3y + 4 = 0 , x - 2y + 1 = 0.


Solve these simultaneous equations; 2y + x = 8, 4 + 4y = 8x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning