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Maths
GCSE

Solve (6/x-2)-(2/x+3)=1

Firstly, begin by multiplying both sides of the equation by (x-2) and (x+3), this gives 6(x+3)-2(x-2)=(x+3)(x-2). Expand out the brackets on each side of the equation to give 6x+18-2x+4=x2-2x+3...

RH
Answered by Ryan H. Maths tutor
5628 Views

Factorise the equation below (1)

(1) x2 + 15x + 56 = 0

56 = 1 x 56, 2 x 26, 4 x 14, 7 x 8

7 + 8 = 15

Hence, factorised equation is (x + 7)(x + 8) = 0

FT
Answered by Fraser T. Maths tutor
2978 Views

When (x – 2)^2 + 7 has a minimum value, what is the value of x?

First, expand (x-2)2:

= (x-2)(x-2),

= x2 - 2x - 2x + 4

= x2 - 4x + 4

Add on the +7:

= x2 - 4x + 11

<...

TL
Answered by Tom L. Maths tutor
6397 Views

How do I calculate the gradient of a non linear equation at a given point?

As we know, to find a gradient in a linear function, we have to calculate the difference in the objective function (usually y) by the difference in the choice variable (commonly x), you may know this as r...

ML
Answered by Milo L. Maths tutor
4633 Views

A) Multiply out 6(n - 2). B) Factorise psquared - 5p

A) 6n - 12

B) p(p-5)

AW
Answered by Ally W. Maths tutor
6706 Views

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