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Solve these simultaneous equations: 2x + y = 7, and 3x - y = 8. Do so by 1) Eliminating an Unknown and 2) Substitution.

The number 'in front of' an unknown is called the Coefficient. When eliminating an unknown, look to see whether the coefficients of x are the same in both equations, or if the coefficients of y are ...

Answered by Ellie H. • Maths tutor

3156 Views

Complete the square and find the roots (where y=0) of: "x^2+4x-5"

completing the square: (x+2)^2-9 finding the roots: (x+2)^2=9 x+2=+/-3 at y= 0, x= -5 or 1

Answered by Liam Q. • Maths tutor

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Expand and simplify (-2x+3)(x-6)

(-2x+3)(x-6)=

-2x^2+12x+3x-18=

-2x^2+15x-18

Answered by Beth C. • Maths tutor

4427 Views

Increase £190 by 25%

There are two ways to work out the answer to this question. The first way involves first working out 25% of £190 and then adding this to your original £190. To calculate 25% of £190 we multiply 190 by 0.2...

Answered by Juliet F. • Maths tutor

5678 Views

How do I solve these two equations simultaneously: 7x+y=1 and 2x^2 - y = 3

These types of questions can sometimes throw people off due to the quadratic nature of the second equation but don't fret; we'll use a method called substitution to find the answer!