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Maths
GCSE

Solve the simultaneous equations: 5x + 3y = 41 and 2x + 3y = 20 Do not use trial and error.

  1. 5x + 3y = 41   2) 2x + 3y = 20 Subtract equation 2) from equation 1) to cancel the y's (3y-3y = 0) .  Next we subtract  the x's (5x - 2x = 3x) and then finally we have 41 - 20 = 21. We now have that...
DT
Answered by David T. Maths tutor
18497 Views

Solve the equation "x^2 + 3x - 4 = 0".

Recognise that quadratic can be factorised:

(x+4)(x-1)=0

This gives the solutions x=-4 and x=1 by inspection.

ZK
Answered by Zak K. Maths tutor
3124 Views

3x² = 75 Find the value of x.

First Simplify the numbers we know. Therefore we get:       x2=75/3      which is the same as     x2=25

Now find the square root of 25, which is 5 or -5. Therefore x=5 or -5

DB
Answered by Daniel B. Maths tutor
19418 Views

How do you expand brackets in a quadratic equation?

To expand the brackets in a quadtratic equation you should multiply whatever is outside the bracket by that which is inside the bracket. For example: 2(x+3) First multiply the first part of the bracket wi...

DH
Answered by Dorothy H. Maths tutor
4483 Views

Express the recurring decimal 0.2131313 as a fraction

  1. Firstly, identify the recurring portion of the decimal. In this case, it is "13"

  2. set up an equation "x=0.2131313

  3. You need to place the repeatin...

AN
Answered by Abhijit N. Maths tutor
14873 Views

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