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Firstly we would approach the question by looking at the question by attempting to group together the x terms to solve for x. By looking at the question we can see that the x terms are the denominators so...
Firstly we need to realise that equation 1 (x^2 + y^2 = 9) does not factorise. So once realising this, we must rearrange equation 2 (x + y = 2) so that y = 2 - x. Now we substitute (y = 2 - x) into equati...
(x-5) (x-2)
area= width x lengtharea= (x+5) x (x+3)area= (x+5)(x+3)area= x2 +8x+15
(x(x-2) + 7(x+4) )/ (x+4)(x-2) = 1x(x-2) + 7(x+4) = (x+4)(x-2)x^2 -2x +7x +28 = x^2 -2x +4x -8x^2 +5x +28 = x^2 +2x -83x +36 = 03x = -36x x= -12
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