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Maths
GCSE

Solve the following simultaneous equations: 3y=7+5x (1) 9x=-7y-4 (2)

Rearrange (2): x=(-7y-4)/9Substitute the value of x from (2) into (1): 3y=7+5*(-7y-4)/9 Simplify and rearrange for y: y+(35y/27)=(7/3) -(20/27)Resolve for y: y=43/62Substitute y into (1): (3*63)/62=7+5xRe...

TD
Answered by Tutor510286 D. Maths tutor
2996 Views

Solve x(x-1)-12=0

Expand the brackets to find x2-x-12=0Factorise the equation to find (x-4)(x+3)=0Check it expands to equal x2-x-12=0Find the value of x as:x+4=0 therefore X=4x-3=0 therefore X=-3

SW
Answered by Sarah W. Maths tutor
2855 Views

Factorise fully X^2 - 6X + 8

Factorising means reducing an equation to a set of brackets, in the form (x+a)(x+b), where a and b are constants. To factorise this equation, we must find two numbers that add to make -6, and multiply to ...

DD
Answered by Dan D. Maths tutor
3529 Views

Solve the following equation: x^2- x - 12 = 0

When looking at this equation, we need to think of two numbers that multiply together to give 12 and have a difference of one. We can rewrite the equation as the following: (x-4)(x+3) = 0 Solving for x:Th...

DL
Answered by Daniel L. Maths tutor
2737 Views

3/(x-1) - 2/(x+1) = 1 Solve to find the values of x.

3(x+1) - 2(x-1) = 1(x-1)(x+1)3x + 3 - 2x + 2 = x2 - 1x2 - x - 6 = 0(x - 3)(x + 2) = 0x = 3 x = -2

EB
Answered by Ece B. Maths tutor
2834 Views

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