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In this question, we are asked to 'expand' out the brackets. What this means is we need each term in one set of brackets (5x and -2y) to be multiplied by each term in the other set of ...

Factorising a quadratic polynomial of the form,

ax² + bx + c = 0

can be done in many depends depending on the values we have for a, b and c. 

Some s...

To solve this quadratic equation we should first see if it is possible to factorise it into two seperate brakets. In this case there are no numbers which multiply to give -5 and add to give 3. Thus we ...

This is a typical exam question which some students may find confusing.The trick to this question is realising that you have to rationalise the denominator. (Topic: Surds)4/(2-√2) = 4/(2-√2) x (2+√2)/(2+√...

3x+6=(x+2)(x-4)

3x+6 = x²-2x-8

x²-5x-14=0

(x-7)(x+2)=0

x=7 so y=27

and x=-2 so y=0