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Maths
GCSE

How can I find the stationary points of a parabola given it's equation?

You can find the stationary points by differentiating the equation and then solving it for zero. What this means, is that you can take the power of the Xs in the equation, and differentiate by bringing th...

MA
Answered by Miriam A. Maths tutor
6086 Views

Solve algebraically the simultaneous equations 2x^2-y^2=17 and x+2y=1

To solve these equations, we have to rearrange the second equation to make x ‘the subject’ and then we can substitute it into the first one. First, subtract 2y from both sides so x=1-2yNext substitute thi...

BH
Answered by Benjamin H. Maths tutor
14923 Views

Factorise 3xy+6x^2

3xy+6x^2There is a common factor of x in both terms so we can factor x out of the expressionx(3y+6x)There is also a common factor of 3 in both terms so we can factor that out also3x(y+2x)

DS
Answered by Dominic S. Maths tutor
6282 Views

Solve these simultaneous equations (1) 12x + 3.5y = 32 (2) 8x + 3y = 24

Make the like terms equate by multiplying (1)*2 and (2)*3, ((1)*2) 24x+7y=64, ((2)*3) 24x+9y=72, Take one away from the other to remove the x term and solve for y, (24x+9y=72) - (24x+7y=64), 2y=8 y=4, Su...

KJ
Answered by Karen J. Maths tutor
2703 Views

A scalene triangle has side lengths a=xcm, b=10cm and c=15cm. The angle A=105 degrees is opposite side a. Using the cosine rule, find the value of x to 3 s.f.

The cosine rule= a2 = b2+c2-2bcCos(A)a2= 102+152-(2x10x15xCos(105))a2= 402.65...Square root of ans.a= 20.07x=20.1cm

LR
Answered by Laurie R. Maths tutor
3076 Views

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