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Maths
GCSE

Make s the subject of: v^2= u^2+2as

The aim of this question is to algebraically manipulate the equation to end up with an equation with s on its own, on one side, making it the subject of the equation.We will start by looking at the terms ...

DD
Answered by Divya D. Maths tutor
61207 Views

Prove algebraically that 0.256565656... can be written as 127/495

Let x = 0.2565656...Then 10x = 2.565656.... and 1000x = 256.565656...So 1000x - 10x = 256.565656... - 2.565656... = 254990x = 254 x = 254/990 = 127/495

OT
Answered by Oliver T. Maths tutor
15535 Views

Solve the simultaneous equations algebraically.

x^2 + y^2 = 29y - x = 3Rearrange the second equation such that one variable, either x or y, is the subject. I will rearrange to make x the subject. x = y - 3. Substitute the new equation into equation 1 i...

JA
Answered by Jane A. Maths tutor
3036 Views

Prove that (3n+1)²-(3n-1)² is a multiple of 4 taking into account that n is a positive integer value

  1. Square the brackets (3n+1)²= (3n+1)(3n+1) = 9n²+3n+3n+1 = 9n²+6n+1 (3n-1)²= (3n-1)(3n-1) = 9n²-3n-3n+1 = 9n²-6n+12. Write out the full equation (9n²+6n+1) - (9n²-6n+1) = 9n²+6n+1-9n²+6n-1 = 12n3. Ex...
NK
Answered by Nalin K. Maths tutor
7043 Views

How do you solve two simultaneous equations? (i.e. 5x + y =21 and x - 3y =9)

There are two ways of solving the simultaneous equations. The easiest one is to write two equations beneath each other and then try to get either x or y values the same on both of them by multiplying the ...

PM
Answered by Paulina M. Maths tutor
3139 Views

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