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From the equation x²+y²-8x+10y+41=0, we can find the centre of the circle by the middle two terms -8x+10y and multiplying them by -1/2. So the coordinates of the circle centre are (4...

We know 2 equations for a straight line; Y=MX+C and Y-B=M(X-A). Since we do not have the y intercept (C) or any means of finding it but we do have 2 points on the straight line, it would make sen...

The formula to be used here is C = Q / V. Where C = capacitance, Q = charge and V = potential difference. First we can put in the values to get 25 * 10^-6 = Q / 500. This can be rearranged to Q = 500 * 25...

Answer is 2x - 4. This is found by following the standard differentiation procedure of n(ax-b)^n-1 where n was the previous power and a and b are the value inside the bracket. This means that it first goe...

b = B/2A = 8/(2x2) =8/4 = 2
c = C-((B^2)/4A) = 30-((8^2)/(4x2)) = 30-64/8 = 30-8 = 22
=> 2x^2 + 8x + 30 = 2(x+2)^2 + 22