Express '2x^2 + 8x + 30' in the form 'a(x+b)^2 + c'

b = B/2A = 8/(2x2) =8/4 = 2
c = C-((B^2)/4A) = 30-((8^2)/(4x2)) = 30-64/8 = 30-8 = 22
=> 2x^2 + 8x + 30 = 2(x+2)^2 + 22

CC
Answered by Charles C. Maths tutor

4598 Views

See similar Maths Scottish Highers tutors

Related Maths Scottish Highers answers

All answers ▸

Find the gradient of the straight line with equation 4x+3y=12


A circle has equation x^2+y^2-8x+10y+41=0. A point on the circle has coordinates (8,-3). Find the equation of the tangent to the circle passing through this point.


Find an equation for the straight line AB , giving your answer in the form px+qy=r, where p, q and r are integers. Given that A has co-ordinates (-2,4) and B has co-ordinates (8,-6)


A circle has equation x^2+y^2+6x+10y-7=0. Find the equation of the tangent line through the point on the circle (-8,-1).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning