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How do you find the stationary points of the curve with equation y=4x^3-12x+1

The stationary points are located where the gradient of the function is equal to 0. The first derivative of the function describes the gradient so we must differentiate the function to find dy/dx.
U...

PL
Answered by Polly L. Maths tutor
7880 Views

Factorise 2(x^2) +7x+3

Only factors of 2 are 1 and 2, therefore solution will take form of (2x + a)(x + b) to get 2x2 term. Only factors of 3 are 1 and 3 therefore a and b are either 1 or 3. Playing around and intuit...

AR
Answered by Albert R. Maths tutor
5157 Views

Simplify (3x^2 + x -2)/(x^2 - 1)

First notice that no simplifications can be made to the problem without changing the form. We start by factorising the numerator. The highest power of x in this question is 2, therefore we know that it ha...

AA
Answered by Arjun A. Maths tutor
4342 Views

Integrate x^3 * lnx

I would start by asking the student the different forms of integration we know (e.g. substitution, parts).I would then ask the student whether parts or substitution gives the easiest method.If the student...

AA
Answered by Arjun A. Maths tutor
2974 Views

Find the stationary points and their nature of the curve y = 3x^3 - 7x + 2x^-1

To start, we need to know that the gradient of the curve at the stationary points is 0 and that when the second derivative is less than 0, there is a maximum and when the derivative is greater than 0, the...

AA
Answered by Arjun A. Maths tutor
4365 Views

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