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A circle has equation x^2+y^2-8x+10y+41=0. A point on the circle has coordinates (8,-3). Find the equation of the tangent to the circle passing through this point.

From the equation x²+y²-8x+10y+41=0, we can find the centre of the circle by the middle two terms -8x+10y and multiplying them by -1/2. So the coordinates of the circle centre are (4...

Answered by Joseph K. • Maths tutor

1991 Views

In trigonometry , how do you find the angles of a right angle triangle?

In order to do that, and this only works for right angled triangles, is using the sine, cosine, and tangent rules. An easy way to remember this is by using the acronym SOH, CAH, TOA that my teacher taught...

Answered by Paulina W. • Maths tutor

4264 Views

Solve: 4(3x − 2) = 2x - 5

The question is asking us to find the value of x. First, we need to multiply the brackets out. To do this, multiply everything in the bracket by 4 so 43x=12x and 4-2=-8 this gives the equation 12...

Answered by Ellecia S. • Maths tutor

13444 Views

The equation kx^2 + 4x + (5 – k) = 0, where k is a constant, has 2 different real solutions for x. Show that k satisfies k^2-5k+4>0.

This questions is a proof type question, which means that you need to get to a specific formula. Usually, these questions give you clues in order to prove it. In this case it tells you that the equation h...

Answered by Alin G. • Maths tutor

15776 Views

Find an equation for the straight line AB , giving your answer in the form px+qy=r, where p, q and r are integers. Given that A has co-ordinates (-2,4) and B has co-ordinates (8,-6)

We know 2 equations for a straight line; Y=MX+C and Y-B=M(X-A). Since we do not have the y intercept (C) or any means of finding it but we do have 2 points on the straight line, it would make sen...

Answered by Samantha C. • Maths tutor

3896 Views