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Differentiate: f(x)=2(sin(2x))^2 with respect to x, and evaluate as a single trigonometric function.
f(x) = 2sin2(2x)Therefore, using the chain rule: f'(x)=2 x 2cos(2x) x 2sin(2x)(The 2 at the front arises from the constant 2, at the start of f(x), the 2cos(2x) comes from differentiating sin
