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You can split the derivative into 2 parts: dx/dy (x^2*e^x) + dx/dy (x)
For the first part you have to use the product rule, so let U=x^2 V=e^x U'=2x V'=Chain rule
V'=dx/dy(e^x)dx/dy(x)...
The first thing we want to do is re-write the curve f(x) in a format in which we can read and easily plot a graph. If we can include the '3x' in the factorised part of the equation, it will be neater and ...
In order to find the gradient of the curve at (1,1), we must first differentiate the equation of the curve. To do this, multiply the coefficient of x by the power of that same x. Then subtract one from th...
No it is not parallel, here is the reasoning.
First we work out the gradient of the line AB. We do this by using the gradient formula (Y2-Y1)/(X2-X1). Our points are A=(1,3) rewritten as (X1,Y1) an...
First, expand out the brackets. Initially, this will give you 20 - 4√3 + 5√12 - √36.
√36 is the equivalent of 6, now giving up 20 - 4√3 + 5√12 - 6. We can combine the 20 and the 6 to give us 14 - 4...
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