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This is a very common IB-level question,
which is solved with using the technique of a "disguised quadratic".
The first thing we want to do in finding the inverse is swapping the p...
to work this out you need to make the equation equal to C so it will look like C=A+B or something similar. to achieve this you need to change the equation so that C only appears on one side. you would nee...
Firstly we need to use product rule to find the dy/dx of the left hand side (LHS). Using implicit differentiation, we know the differential of y^2 is 2y(dy/dx). Then use to product rule to obtain the dy/d...
mathematical derivation
To do this we will use the chain rule, whereby dy/dx = dy/du * du/dx. So if y = (ax^2+bx+c)^n then we will say that u = ax^2+bx+c. Therefore y =u^n. So to find dy/dx we differentiate u with respect to x, ...
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