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Solve the equation 3^(2x+1)=1000

We can use logarithms with base 3 to solve this equation.2x+1=log310002x=log3(1000)-1x=0.5(log3(1000)-1)x=2.64

SD
Answered by Samuel D. Maths tutor
4768 Views

Integrate 6/(e^x+2) between 1 and 0

By Trapezium Rule (with 5 segments)x 0 0.2 0.4 0.6 0.8 1y 2 1.8625 1.71830 1.56981 1.41994 1.27165≈1⁄2*(0.2) [2+1.27165+ 2( 1.8625 + 1.71830 + 1.56981 + 1.41994)]≈1⁄10 *16.41283 = 1.641By Substitution/ Pa...

CH
Answered by Christopher H. Maths tutor
4128 Views

Binomially expand the equation (2+kx)^-3

(2+kx)-3 = (2-3)(1+kx/2)-3 = (2-3)(1+(-3)(kx/2) + [(-3)(-4)]/2! (kx/2)2 + [(-3)(-4)(-5)]/3! (kx/2)3 +... )
= 1⁄8 [1 -(3kx/...

CH
Answered by Christopher H. Maths tutor
8756 Views

Solve the simultaneous equations: 2x + y = 18, x - y =6.

There are 2 different ways to approach solving simultaneous equations: 1) making x or y the subject of one of the equations.2) addition or subtraction method.In this section, I will explain the first meth...

JG
Answered by Jamini G. Maths tutor
15562 Views

Express 112 as a product of it's prime factors.

The easiest way to approach this problem is using a break down tree from the number at the top of the page. Firstly, you can divide 112 by 2 to get 56. Circle the number 2 as this is prime and can no long...

AB
Answered by AIDAN B. Maths tutor
10152 Views

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