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By Trapezium Rule (with 5 segments)x 0 0.2 0.4 0.6 0.8 1y 2 1.8625 1.71830 1.56981 1.41994 1.27165≈1⁄2*(0.2) [2+1.27165+ 2( 1.8625 + 1.71830 + 1.56981 + 1.41994)]≈1⁄10 *16.41283 = 1.641By Substitution/ Pa...

(2+kx)^-3 = (2^-3)(1+kx/2)^-3 = (2^-3)(1+(-3)(kx/2) + [(-3)(-4)]/2! (kx/2)² + [(-3)(-4)(-5)]/3! (kx/2)³ +... )
= 1⁄8 [1 -(3kx/...

There are 2 different ways to approach solving simultaneous equations: 1) making x or y the subject of one of the equations.2) addition or subtraction method.In this section, I will explain the first meth...

The easiest way to approach this problem is using a break down tree from the number at the top of the page. Firstly, you can divide 112 by 2 to get 56. Circle the number 2 as this is prime and can no long...

recognise this equation has the form ax^2 + bx + c =0. An equation with this form is a quadratic. Recognise in a quadratic equation there will be 2 values of x that will equal 0. These 2 values wil...