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equation(1) h = 3t^2 a) find h when t=5 b)find t when h=108

for part AYou would but the t² into brackets , then substitute t=5 to get h=3(5²) using BIDMAS do the 5² = 25 so that h=3(25) so you end up with h=75
for part B fir...

Answered by Danielle N. • Maths tutor

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If a curve has equation y = (-8/3)x^3 - 2x^2 + 4x + 18, find the two x coordinates of the stationary points of this curve.

The first step in solving this question is to differentiate equation y with respect to x. To differentiate a given 'x' term in an equation use the following method --> xⁿ becomes nx^(n-1...

Answered by Robyn T. • Maths tutor

3071 Views

A curve has equation y=x^2 + 2x +5. Find the coordinates of the point at which the gradient is equal to 1.

dy/dx= 2x+2 , gradient is equal to 1 so dy/dx also equals 1.1=2x+2-1=2xx=-1/2plug this value of x into the equation to get y=17/4

Answered by Nikhil L. • Maths tutor

3528 Views

Find the derivative, dy/dx, of y = 8xcos(3x).

Let u= 8x then du/dx = 8Let v= cos(3x) then dv/dx = -3sin(3x)Therefore using the product rule: dy/dx = (cos(3x))(8) + (8x)(-3sin(3x))So dy/dx = 8cos(3x) - 24xsin(3x) .

Answered by Joshua C. • Maths tutor

3252 Views

3x + x = 12. Find x

Due to the fact that the two 'x' in the question do not have a power (Are not squared or cubed) they can be added. Thus:4x = 12Then we want to find 'x' so we isolate it in the equation. To do this, we nee...

Answered by Tanika D. • Maths tutor

1660 Views