Top answers

Maths
All levels

What is mathematical induction and how does it work?

Mathematical induction is a method of proving if a mathematical statement is true for all natural numbers. To start with, I am going to give an analogical example in order to have a better understanding. ...

BD
Answered by Borja D. Maths tutor
3038 Views

A 2.4 m long plank of mass 20kg has 2 pins, each 0.5 meters from each respective plank end. A person of mass 40kg stands on the plank 0.1m from one of the pins. Calculate the magnitude of reactions at the pins for this structure to be in equilibrium.

1.) draw what is happening: 2.)Notice key points of questions: Plank is in equilibrium. This means that all forces=0 and all moment=03.) Apply force equilibrium: 4.) Apply moment equilibrium5.) fin...

ST
Answered by Samuel T. Maths tutor
2808 Views

Solve 5x + 3 = 45

5x + 3 = 455x + 3 - 3 = 45 - 3 (subtract 3 from both sides)5x = 42(5x)/5 = 42/ 5 (divide both sides by 5)x = 8.4 (can either be expressed as a decimal or as fraction)

CA
Answered by Caroline A. Maths tutor
3825 Views

Three identical isosceles triangles are joined together to make a trapezium. Each triangle has base b cm and height h cm. Work out an expression, in terms of b and h for the area of the trapezium.

Formula for the Area of a triangle: A = (base x height)/ 2
Here we have three identical triangles.
Therefore the formula for the Area of the three triangles: A = (b x h) x 3 / 2 = A of trapeziu...

MC
Answered by Megan C. Maths tutor
8854 Views

Solve the differential equation csc(x)*dy/dx=exp(-y), given that y(0)=0. (Typical Math HL paper 3 question, Calculus optional topic)

Firstly, we need to grasp the problem, and understand what the question is asking us to do. We are given a differential equation, and we are required to solve for y, i.e. write y as a function of x: y(x)=...

KG
Answered by Khariton G. Maths tutor
1696 Views

We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning