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As x is present as both numerator and denominator (top & bottom), we're going to use the quotient rule to solve this. The quotient rule is as follows:For y=f(x)/g(x), dy/dx=(f'(x).g(x)-f(x).g'(x)...

Differentiate the function to find the gradient at any point: df/dx = 2x - 1/(x+3)^2 - 4/(x^5)insert the value of 2 into f(x) and df/dx --> df/dx = 3.835, f(2) = 4.2625create the equation of the line b...

Start by looking for multiples of 10. You have the pairs 2 & 5 and 1 & 10. Both signs are positive in the original equation so it will either be positive 2 & 5 or positive 1 & 10. Clearly ...

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12x^2-6x+9