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The line L1 has vector equation, L1 = ( 6, 1 ,-1 ) + λ ( 2, 1, 0). The line L2 passes through the points (2, 3, −1) and (4, −1, 1). i) find vector equation of L2 ii)show L2 and L1 are perpendicular.

i)L(r) vector line equations in general are in the form L(r) = p1 + λ (p2) where p1 is any ponit on the line and p2 is the vector direction of the line(unsure how to get the whiteboard up or i would descr...

Answered by Charles E. • Maths tutor

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Factorise 12x^2 - 20x + 3

We know our answer is going to look like this: (ax + b)(cx + d).
First we can split our original equation in order to make it easy to simplify. As we know that 12 multiplied by 3 is equal to 36 we c...

Answered by Emma G. • Maths tutor

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The straight line with equation y=3x-7 does not cross or touch the curve with equation y=2px^2-6px+4p, where p is a constant.(a) Show that 4p^2-20p+9<0 (b) Hence find the set of possible values for p.

(a) If we consider the intersection of these two lines then, 3x-7=2px^2-6px+4p.This can be rearranged into the form ax^2+bx+c=0 such that, 2px^2+(-6p-3)x+4p+7, where a=2p, b=-6p-3 and c=4p+7.However, sinc...

Answered by Will G. • Maths tutor

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How do you differentiate using the chain rule?

The chain rule is used where the equation you are looking to differentiate is a function that is itself raised to a power. For example, we might have y = (x²-2)³ and want to differen...

Answered by Oliver B. • Maths tutor

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